The problem can be found at the following link: Question Link
The problem is about playing a game with a given string where the goal is to minimize the string's value. We count the frequency of each character in the string and repeatedly remove the most frequent character k times. Then, we calculate the sum of squares of the remaining frequencies, which represents the value of the resulting string.
- We first count the frequency of each character in the string using an unordered map.
- We use a priority queue to store the frequencies of characters. This allows us to easily remove the most frequent character each time.
- We repeatedly remove the most frequent character k times and update the priority queue accordingly.
- After the removal process, we calculate the value of the resulting string by summing the squares of the remaining frequencies.
- Time Complexity: The time complexity of the solution is
O(n + k log m)
, where n is the length of the string, k is the given integer, and m is the number of unique characters in the string. - Auxiliary Space Complexity: The auxiliary space complexity is
O(m)
, where m is the number of unique characters in the string, due to the usage of the unordered map and priority queue.
class Solution {
public:
int minValue(string s, int k){
unordered_map<char,int> mp;
for(auto i: s){
++mp[i];
}
priority_queue<int> pq;
for(auto i: mp)
pq.push(i.second);
while(k--){
int t = pq.top();
pq.pop();
--t;
if(t) pq.push(t);
}
int out = 0;
while(!pq.empty()){
out += pq.top() * pq.top();
pq.pop();
}
return out;
}
};
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